Discussion
A student reports a potential of 500 V and a field of 500 V/m at the same point, 1 m from a point charge. The relation between the two figures is
Answer: A
For a point charge the potential is \( Q/4\pi\epsilon_0 r \) and the field is that again divided by r, so at one metre they take the same numerical value. At two metres the potential would be 250 V and the field 125 V/m.
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