Discussion
A potential function is given as \( V = xyz \). The field at the point \( (1, 1, 1) \) is
Answer: A
The three partial derivatives of \( xyz \) are \( yz \), \( xz \) and \( xy \), each of which is one at the given point, and reversing the sign gives the field. The magnitude of the field there is therefore the square root of three, directed along the negative of the diagonal through the origin.
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