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The reactive power needed to raise a load's power factor from \( \cos\phi_1 \) to \( \cos\phi_2 \) is

  • A.\( P(\tan\phi_1 - \tan\phi_2) \)
  • B.\( P(\cos\phi_1 - \cos\phi_2) \)
  • C.\( P(\sin\phi_1 - \sin\phi_2) \)
  • D.\( S(\tan\phi_1 - \tan\phi_2) \)

Answer: A

The active power is fixed, so the reactive power at each factor is that active power multiplied by the tangent of the corresponding angle, and the capacitor supplies the difference. Using the apparent power instead is the commonest slip.

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