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Reducing that cable's current to 80 A by correcting the power factor changes the loss to

  • A.320 W
  • B.400 W
  • C.500 W
  • D.250 W

Answer: A

The square law gives \( 80^2 \times 0.05 = 320 \) watts, a reduction of thirty-six per cent for a twenty per cent reduction in current. That squaring is why correction at the load, rather than at the incoming panel, is worth so much on a long run.

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