Discussion
The pH of the mixture of 800 ml of 0.1 M HCl and 200 ml of 0.3 M NaOH is close to :
Answer: D
The pH is close to 1.70.
\[ \begin{aligned} n(\text{H}^{+}) &= 0.800 \times 0.1 = 0.080\ \text{mol} \\ n(\text{OH}^{-}) &= 0.200 \times 0.3 = 0.060\ \text{mol} \\ \text{excess H}^{+} &= 0.020\ \text{mol in } 1.0\ \text{L} \end{aligned} \]
\[ \text{pH} = -\log(0.020) = 1.70 \]
The original 0.1 M HCl had pH 1.00, so 1.10 is too acidic once 0.060 mol of the acid has been neutralised. 13.3 would mean excess base, and 6.90 near-exact neutralisation, but the acid is in excess by 0.020 mol in the combined 1 L.
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