Discussion
What volume of O2(g) is produced when 2F current is passed through a very dilute aqueous solution of H2SO4 at STP?
Answer: D
The volume of oxygen is 11.2 dm3.
At the anode, water is oxidised: \(2\text{H}_{2}\text{O} \rightarrow \text{O}_{2} + 4\text{H}^{+} + 4e^{-}\). One mole of \(\text{O}_{2}\) needs 4 F.
\[ \begin{aligned} n(\text{O}_{2}) &= \frac{2}{4} = 0.5\ \text{mol} \\ V &= 0.5 \times 22.4 = 11.2\ \text{dm}^{3} \end{aligned} \]
22.4 dm3 is the volume of hydrogen released at the cathode by the same 2 F, since each \(\text{H}_{2}\) needs only 2 electrons.
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