Discussion
For the cell Zn | Zn\( ^{2+} \) || Cu\( ^{2+} \) | Cu with standard potentials \( -0.76 \) V and \( +0.34 \) V, the standard EMF is
Answer: C
Correct answer: 1.10 V
Copper is the cathode and zinc the anode, so
\[ E^\circ = E^\circ_{cathode} - E^\circ_{anode} = 0.34 - (-0.76) = 1.10 \ \mathrm{V} \]The positive result confirms that the cell as written is spontaneous. Adding the two potentials instead would give \( -0.42 \), and subtracting the wrong way round gives \( -1.10 \) - both of the distractors offered.
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