Discussion
The mass of copper deposited by 2 A flowing for 30 minutes, taking the equivalent mass as 31.75, is about
Answer: B
Correct answer: 1.18 g
Applying Faraday’s laws,
\[ m = \frac{E \times I \times t}{F} = \frac{31.75 \times 2 \times 1800}{96\,500} = \frac{114\,300}{96\,500} \approx 1.18 \ \mathrm{g} \]The time must be in seconds, so the thirty minutes becomes 1800. Using the atomic mass of 63.5 instead of the equivalent mass would double the answer, which is the error the 2.37 g distractor represents.
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