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A 0.1 N solution of specific conductance 0.0129 S/cm has an equivalent conductance of

  • A.129 S cm\( ^2 \)/eq
  • B.12.9 S cm\( ^2 \)/eq
  • C.1290 S cm\( ^2 \)/eq
  • D.0.129 S cm\( ^2 \)/eq

Answer: A

Correct answer: 129 S cm\( ^2 \)/eq

Applying the relation,

\[ \Lambda = \frac{1000\kappa}{N} = \frac{1000 \times 0.0129}{0.1} = 129 \ \mathrm{S\,cm^2/eq} \]

The 1000 converts the litre of the normality to the cubic centimetres of the specific conductance, and forgetting it is the commonest error - giving 0.129 instead.

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