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Given \( \Lambda^\circ \) of HCl as 426, of CH\( _3 \)COONa as 91 and of NaCl as 126, Kohlrausch's law gives \( \Lambda^\circ \) of acetic acid as

  • A.209
  • B.391
  • C.643
  • D.461

Answer: B

Correct answer: 391

Kohlrausch’s law of independent migration lets the ions be added and subtracted:

\[ \Lambda^\circ_{\mathrm{HAc}} = \Lambda^\circ_{\mathrm{HCl}} + \Lambda^\circ_{\mathrm{CH_3COONa}} - \Lambda^\circ_{\mathrm{NaCl}} \]\[ = 426 + 91 - 126 = 391 \]

The sodium and chloride ions cancel, leaving hydrogen and acetate. This is the only route to a weak electrolyte’s limiting conductance, since it cannot be reached by extrapolation.

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