Discussion
If an inductor coil of self-inductance 2 H stores 25 J of magnetic energy, then the current I passing through it is
Answer: E
The current is 5 A.
The energy stored in an inductor is \(U = \frac{1}{2}LI^{2}\).
\[ \begin{aligned} 25 &= \tfrac{1}{2}(2)I^{2} \\ I^{2} &= 25 \Rightarrow I = 5\ \text{A} \end{aligned} \]
25 A is \(I^{2}\), not I. 10 A doubles the answer, and 2 A confuses the current with the inductance.
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