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If an emf of 2 V is induced in a coil in 6 s, then the change of flux (in Wb) in the coil during the time is

  • A.3
  • B.24
  • C.6
  • D.18
  • E.12

Answer: E

The change of flux is 12 Wb.

By Faraday's law, the magnitude of the induced emf equals the rate of change of flux, \(e = \frac{\Delta\phi}{\Delta t}\).

\[ \Delta\phi = e \times \Delta t = 2 \times 6 = 12 \text{ Wb} \]

Here the emf is taken as steady over the 6 s, so the flux changes at a constant 2 Wb per second; one weber per second is one volt. 3 Wb comes from dividing 6 by 2 instead of multiplying, and the other values do not follow from the law.

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