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The plane of a circular loop of area 150 cm2 is perpendicular to a uniform magnetic field of 0.5 T. If the loop is turned such that its plane is in the direction of the field in 0.5 s, then the induced emf produced is

  • A.25 mV
  • B.10 mV
  • C.2.5 mV
  • D.15 mV
  • E.7.5 mV

Answer: D

The induced emf is 15 mV.

Initially the plane is perpendicular to the field, so the flux is \(BA\). When the plane lies along the field, the flux is zero. The average emf is the change in flux divided by the time:

\[ \begin{aligned} \Delta\phi &= 0.5 \times 150 \times 10^{-4} = 7.5 \times 10^{-3} \text{ Wb} \\ e &= \frac{7.5 \times 10^{-3}}{0.5} = 1.5 \times 10^{-2} \text{ V} \end{aligned} \]

That is 15 mV. 7.5 mV is the flux change in milliwebers, forgetting to divide by the 0.5 s.

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