Discussion
Two identical transformers A and B each with \(\frac{N_{p}}{N_{s}} = 2\) are connected such that the secondary output obtained from A is given as the primary input voltage for B. If the primary ac voltage of A is 200 V, then the secondary voltage from B is
Answer: C
The secondary voltage from B is 50 V.
For a transformer \(\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}}\). With \(\frac{N_{p}}{N_{s}} = 2\), each transformer halves the voltage (step-down).
\[ \begin{aligned} \text{after } A &: 200 \div 2 = 100 \text{ V} \\ \text{after } B &: 100 \div 2 = 50 \text{ V} \end{aligned} \]
100 V is the output of A alone, and 400 V treats the transformers as step-up.
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