Discussion
In a plane electromagnetic wave, the magnetic field is given by \(B = 400 \times 10^{-6} \sin[(4.0 \times 10^{-4})(t - x / c)]\) T .The peak value of electric field (in \(Vm^{-1}\)) is
Answer: E
The peak electric field is \(12 \times 10^{4}\ \text{V m}^{-1}\).
In an electromagnetic wave, \(E_{0} = cB_{0}\). Here \(B_{0} = 400 \times 10^{-6}\) T:
\[ \begin{aligned} E_{0} &= 3 \times 10^{8} \times 4 \times 10^{-4} \\ &= 1.2 \times 10^{5} = 12 \times 10^{4}\ \text{V m}^{-1} \end{aligned} \]
The angular frequency in the argument does not affect the amplitude. \(4 \times 10^{4}\) and the other options come from dropping the factor 3 in c or a power of ten.
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