Discussion
In a plane electromagnetic wave if the amplitude of oscillating electric field is 45 Vm-1 then the amplitude of the oscillating magnetic field is
Answer: B
The magnetic field amplitude is \(1.5 \times 10^{-7}\) T.
In an electromagnetic wave the field amplitudes are related by \(E_0 = cB_0\).
\[ \begin{aligned} B_0 &= \frac{45}{3 \times 10^{8}} \\ &= 1.5 \times 10^{-7}\ \text{T} \end{aligned} \]
\(1.5 \times 10^{-8}\) T is the same digits with the power of ten slipped by one. The ratio \(\frac{E_0}{B_0} = c\) holds for any electromagnetic wave in vacuum, whatever its frequency.
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