Discussion
The rate of fall of the voltage across the capacitor in a filter used in a diode rectifier depends
Answer: E
The rate of fall depends on the inverse of the product of the capacitance and effective load resistance.
Between peaks, the filter capacitor discharges through the load. Its voltage falls as \(V = V_0e^{-t/RC}\), so the rate of fall is governed by \(\frac{1}{R_L C}\). A larger time constant \(R_L C\) means a slower fall and a smoother output, which is why large capacitors are used.
The rate does not depend directly on \(R_L C\), nor on the capacitance alone, nor on a sum or difference of reactance and resistance.
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