Discussion
The quark content of the subatomic particle K° with strangeness S = +1 and isospin I =1/2 is given by :
Answer: A
The quark content is \(d\bar{s}\).
Strangeness is \(-1\) for each \(s\) quark and \(+1\) for each \(\bar{s}\) antiquark. A \(K^{0}\) with \(S = +1\) must contain an \(\bar{s}\); being neutral, it pairs it with a \(d\) quark (charge \(-\frac{1}{3} + \frac{1}{3} = 0\)). The \(d\) gives isospin \(\frac{1}{2}\), and \(K^{0}\) and \(K^{+} = u\bar{s}\) form an isospin doublet.
\(\bar{d}s\) is the \(\bar{K}^{0}\), with \(S = -1\). \(d\bar{d}\) and \(u\bar{u}\) have zero strangeness and appear in the \(\pi^{0}\) and \(\eta\).
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