Discussion
For the given reaction, \(n + \bar{p} \to \pi^{-} + \pi^{0}\) which of the conservation statement is true ?
Answer: D
The correct statement is all conservations hold true, the reaction is allowed.
Check each quantity for \(n + \bar{p} \to \pi^{-} + \pi^{0}\):
- Charge: \(0 + (-1) = -1\) on the left, \(-1 + 0 = -1\) on the right.
- Baryon number: \(+1 + (-1) = 0\) on the left; pions are mesons with \(B = 0\).
- Electron lepton number: no leptons on either side, so 0 = 0.
Nucleon-antinucleon annihilation into pions is a common strong process, and energy is ample since the rest energy of the pair (about 1.88 GeV) far exceeds two pion masses. The three options claiming a violated law each name a quantity that the check above shows to be conserved.
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