Discussion
An aircraft has a neutral point at \( 0.42 \bar{c} \) and requires a minimum static margin of \( 0.05 \). With \( \bar{c} = 4.0 \) m, the aft centre of gravity limit lies at
Answer: A
Correct answer: 1.48 m aft of the reference
The aft centre of gravity limit is the neutral point moved forward by the required static margin:
\[ x_{cg} = 0.42\bar{c} - 0.05\bar{c} = 0.37\bar{c} \]
\[ 0.37 \times 4.0 = 1.48\ \mathrm{m} \]
The distractor 1.68 m is the neutral point itself, which would leave no margin at all, and 1.88 m applies the margin in the wrong direction - aft of the neutral point, where the aircraft would be unstable. The margin must be subtracted, since stability requires the centre of gravity forward.
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