Discussion
Measuring power factor at a feeder is worthwhile in an audit because a poor factor
Answer: B
Correct answer: raises the current for the same useful power
\[ I = \frac{P}{\sqrt{3}\,V\cos\phi}, \] so a low power factor means more current for the same real power. That extra current heats the cables and the transformer, consumes capacity that could carry useful load, and attracts a penalty on most tariffs. It does not reduce the voltage at the load appreciably, nor cause harmonics - though harmonics do reduce the overall power factor.
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