Discussion
A site's electricity meter records 90 000 kWh in a month while the sum of its departmental sub-meters is 78 000 kWh. The unaccounted energy is
Answer: D
Correct answer: 12 000 kWh, some 13 per cent of the total
\[ 90{,}000 - 78{,}000 = 12{,}000\ \mathrm{kWh}, \qquad \frac{12{,}000}{90{,}000} = 13.3\ \mathrm{per\ cent}. \] The proportion is taken against the main meter, which is the true total; taking it against the sub-metered sum gives 15 per cent, which is offered here. Unaccounted energy of this size points to unmetered loads rather than to meter error.
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