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If that boiler delivers 4.7 MW of useful heat in its steam, its efficiency is about

  • A.88 per cent
  • B.81 per cent
  • C.124 per cent
  • D.70 per cent

Answer: B

Correct answer: 81 per cent

The input is \( 500 \times 42 = 21{,}000 \) MJ an hour, which is \( 21{,}000/3600 = 5.83 \) MW. The efficiency is then \[ \frac{4.7}{5.83} = 0.81. \] Note the units must be reconciled first - megajoules per hour against megawatts - and the answer above 100 per cent offered here is what results from dividing the wrong way round.

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