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A smelter using 13 500 kWh per tonne of aluminium consumes, for 100 000 tonnes a year,

  • A.135 GWh
  • B.13 500 GWh
  • C.13.5 GWh
  • D.1350 GWh

Answer: D

Correct answer: 1350 GWh

\[ 13\,500\ \mathrm{kWh/t} \times 100\,000\ \mathrm{t} = 1.35 \times 10^9\ \mathrm{kWh} \] \[ = 1350\ \mathrm{GWh}. \] That is the output of a 150 MW station running continuously, for a single smelter - which is why smelters are built beside hydro schemes and why their power contracts are negotiated over decades.

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