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A 20 kW machine left idling four hours a day for 300 days consumes

  • A.6000 kWh
  • B.24 000 kWh
  • C.2400 kWh
  • D.240 000 kWh

Answer: B

Correct answer: 24 000 kWh

\[ 20\ \mathrm{kW} \times 4\ \mathrm{h} \times 300 = 24\,000\ \mathrm{kWh}. \] This is the archetypal housekeeping saving: nothing is produced during those hours and the remedy costs nothing but discipline. It is also why such savings need continuing attention - the machine will be left running again next month unless someone keeps checking.

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