Discussion
A diode luminaire of efficacy 120 lm/W producing 1500 lm consumes about
Answer: D
Correct answer: 12.5 W
\[ \frac{1500}{120} = 12.5\ \mathrm{W}. \] Flux divided by efficacy gives power, which is the previous calculation run backwards. Multiplying instead of dividing gives 180,000, and inverting the efficacy carelessly gives 125 - the latter offered here.
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