Discussion
Replacing 100 filament lamps of 100 W with equivalent 13 W diode luminaires, running 3000 hours a year, saves about
Answer: A
Correct answer: 26 100 kWh a year
\[ (100 - 13) \times 100 \times 3000 = 26{,}100{,}000\ \mathrm{Wh} = 26{,}100\ \mathrm{kWh}. \] The saving is the difference in wattage, not the new wattage or the old one, so 3,900 and 30,000 are what those two mistakes produce - and both are offered.
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