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An occupancy sensor in a store lit 10 hours a day but occupied 2 hours saves about

  • A.nothing
  • B.80 per cent of that room's lighting energy
  • C.20 per cent of that room's lighting energy
  • D.50 per cent of that room's lighting energy

Answer: B

Correct answer: 80 per cent of that room's lighting energy

\[ \frac{10-2}{10} = 80\ \mathrm{per\ cent}. \] Eight of the ten hours are lit with nobody present, and the sensor removes them. This is why stores, washrooms and meeting rooms are where sensors pay, and why fitting one in a continuously occupied space saves nothing.

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