Discussion
A meter of constant 1200 rev/kWh is on a 1.5 kW load. The time for 10 revolutions is
Answer: A
Ten revolutions represent \( 10/1200 = 0.00833 \) kWh, which at 1.5 kW takes \( 0.00833/1.5 = 0.00556 \) hour, that is 20 seconds. A convenient test interval is one long enough for the stopwatch error to be small, so a slow meter is given more revolutions.
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