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A meter of constant 1200 rev/kWh creeps one revolution in 10 minutes with no load. The equivalent power it is registering is

  • A.50 W
  • B.0.5 W
  • C.300 W
  • D.5 W

Answer: D

One revolution is \( 1/1200 = 8.33 \times 10^{-4} \) kWh, and over a sixth of an hour that is \( 8.33 \times 10^{-4} \times 6 = 5 \times 10^{-3} \) kW, or five watts. Over a month such creeping would register more than three units the consumer has not used.

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