Discussion
Shifting 50 000 kWh from a peak register at 9.60 to an off-peak register at 6.80 saves
Answer: D
Correct answer: 1.40 lakh
The saving is the number of units shifted times the difference in rate: \[ 50\,000 \times (9.60 - 6.80) = 50\,000 \times 2.80 \] \[ = 1\,40\,000 = 1.40\ \text{lakh}. \] Multiplying by the off-peak rate rather than the difference gives 3.40 lakh, which would be the cost of the shifted energy rather than the saving.
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