Discussion
A turboprop develops a torque of \( 3000 \ \mathrm{N\,m} \) at a shaft speed of \( 200 \ \mathrm{rad/s} \). The shaft power is
Answer: A
Correct answer: 600 kW
Shaft power is the product of torque and angular velocity:
\[ P = T\omega = 3000 \times 200 = 600\,000\ \mathrm{W} = 600\ \mathrm{kW} \]
The relation holds only with \( \omega \) in radians per second; a speed given in rpm must first be converted by \( \omega = 2\pi N/60 \). This is precisely why a turboprop needs both a torquemeter and a tachometer - torque alone is not power. In practice the propeller governs at constant rpm, so torque becomes a direct proxy for power at that setting.
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