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If generator efficiency is 90%, the maximum electricity produced, in kW is

  • A.2.85
  • B.3.00
  • C.3.15
  • D.3.50

Answer: C

The maximum electricity produced is 3.15 kW.

The engine is coupled directly to the generator, so the generator receives the full brake power of 3.5 kW. Its electrical output is that shaft input times the generator efficiency:

\[ \begin{aligned} P_{e} &= \eta_{g} \times P_{b} \\ &= 0.90 \times 3.5 = 3.15\ \text{kW} \end{aligned} \]

3.50 kW ignores the generator losses. 3.00 and 2.85 kW would correspond to generator efficiencies of about 86% and 81%, not the 90% given. The engine's thermal efficiency from Q48 plays no part here, because 3.5 kW is already the brake (shaft) output.

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