Discussion
What will be the output of the program?
public class X
{
public static void main(String [] args)
{
try
{
badMethod();
System.out.print("A");
}
catch (RuntimeException ex) /* Line 10 */
{
System.out.print("B");
}
catch (Exception ex1)
{
System.out.print("C");
}
finally
{
System.out.print("D");
}
System.out.print("E");
}
public static void badMethod()
{
throw new RuntimeException();
}
}
Answer: C
Correct answer: BDE
badMethod throws, so the print("A") after it never runs. The first matching catch handles it and prints B - and only one catch block ever runs, which is why no C appears. The finally then prints D, and because the exception was handled rather than propagated, execution continues past the whole statement and prints E. The output is BDE.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development