Discussion
What will be the output of
int x=5; printf("%d", x++);Answer: A
The output is 5.
x++ is the post-increment operator: the expression's value is the current value of x, and x is increased only afterwards. So printf receives 5 and prints 5, and x becomes 6 once the statement is done.
6 would be printed by the pre-increment ++x, which increments first and then uses the new value. 4 would need a decrement, and the code is valid C, so there is no error.
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