Discussion
What is the output of this C code?
int main()
{
int i = -5;
int k = i %4;
printf("%d\n", k);
}
Answer: B
Correct answer: -1
In C the result of % takes the sign of the dividend, and the language requires that (a/b)*b + a%b == a. Since -5 / 4 truncates toward zero to \(-1\), we need \(-1 \times 4 + r = -5\), giving \(r = -1\). So the program prints -1.
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