Discussion

What is the output of this C code?

 int main()
    {
        int x = 2, y = 1;
        x *= x + y;
        printf("%d\n", x);
        return 0;
    }

Answer: D

Correct answer: 6

x *= x + y; means x = x * (x + y) - the whole right-hand side is evaluated first, because compound assignment binds more loosely than +:

\[ x = 2 \times (2 + 1) = 6 \]

There is exactly one modification of x, so nothing here is undefined.

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