Discussion

What is the output of this C code?

 int main()
    {
        int x = 2, y = 2;
        x /= x / y;
        printf("%d\n", x);
        return 0;
    }

Answer: A

Correct answer: 2

x /= x / y; is x = x / (x / y). The right-hand side is computed first, with integer division throughout:

\[ x / y = 2 / 2 = 1, \quad x = 2 / 1 = 2 \]

So x is unchanged at 2.

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