Discussion

What is the output of this C code?

int main()
    {
        int c = 2 ^ 3;
        printf("%d\n", c);
    }

Answer: A

Correct answer: 1

^ is bitwise exclusive OR, not exponentiation - a common trap for anyone coming from a language where ^ means “to the power of”:

\[ 2 = 010_2, \quad 3 = 011_2, \quad 010 \oplus 011 = 001_2 = 1 \]

So c is 1, not 8.

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