Discussion
What is the output of this C code?
int main()
{
int a = 2;
if (a >> 1)
printf("%d\n", a);
}
Answer: C
Correct answer: 2
a >> 1 shifts 2 (binary 10) right by one place, giving 1. That is non-zero, so the condition is true and the body runs, printing the value of a - which the shift never changed, since >> yields a new value rather than modifying its operand. The output is 2.
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