Discussion
What is the output of this C code?
int main()
{
int a = 1, b = 1, c;
c = a++ + b;
printf("%d, %d", a, b);
}
Answer: B
Correct answer: a = 2, b = 1
c = a++ + b; uses the old value of a, so c becomes 2, and the side effect then makes a equal to 2. b is only read, so it stays 1. The printed values are those of a and b, not of c.
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