Discussion
What is the output of this C code?
int main()
{
int i = 10;
int *p = &i;
printf("%d\n", *p++);
}
Answer: A
Correct answer: 10
++ binds tighter than *, but it is a post-increment, so *p++ means “dereference the current p, then advance p”. The value printed is therefore i itself, 10; the pointer moves on afterwards, to an address that is no longer valid.
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