Discussion
What will be the output of the following code snippet?
Y = 5;
if (! Y > 10)
X = Y + 3;
else
X = Y + 10;
printf(" X = %d Y = %d", X, Y);
Answer: A
Correct answer: The program will print X = 15 Y = 5
! binds far tighter than >, so the condition is (!Y) > 10, not !(Y > 10). With Y equal to 5, !Y is 0, and \(0 > 10\) is false. The else branch runs, giving \(X = 5 + 10 = 15\), and Y is never modified, so the output is X = 15 Y = 5.
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