Discussion

How many trailing zeros are in 25! ?

Answer: C

The number of trailing zeros in a factorial is determined by the number of times 5 is a factor in its prime factorization. We can find this using the formula: \(\lfloor n/5 \rfloor + \lfloor n/25 \rfloor + \lfloor n/125 \rfloor + ...\). For 25!, this is \(\lfloor 25/5 \rfloor + \lfloor 25/25 \rfloor = 5 + 1 = 6\). There are 6 trailing zeros.