Discussion
What is the remainder when \((25! + 1)\) is divided by 23?
Answer: B
The factorial 25! is the product \(25 \times 24 \times 23 \times ... \times 1\). Since this product contains the number 23 as a factor, 25! is a multiple of 23.
Therefore, the remainder when 25! is divided by 23 is 0.
The problem then becomes finding the remainder of \((0 + 1)\) when divided by 23, which is simply 1.
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