Discussion
How many trailing zeros are in the result of \(50! \times 20!\)?
Answer: B
When multiplying numbers, the number of trailing zeros in the product is the sum of the number of trailing zeros in each number. Zeros in 50! = \(\lfloor 50/5 \rfloor + \lfloor 50/25 \rfloor = 10+2=12\). Zeros in 20! = \(\lfloor 20/5 \rfloor = 4\). Total zeros = \(12+4=16\).
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