Discussion
A fault with a slip of 50 m along a plane dipping at 30 degrees has a throw of
Answer: C
Correct answer: 25 m
The throw is the vertical component of the slip:
\[ \text{throw} = s\sin\delta = 50 \times \sin 30^\circ = 50 \times 0.5 = 25 \text{ m} \]A shallow-dipping fault therefore gives a small throw for a large slip, which is why a thrust may carry rocks many kilometres horizontally while displacing them only modestly in the vertical.
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