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If that amplifier's open-loop gain now halves to \( 5000 \), the closed-loop gain becomes about

  • A.98
  • B.50
  • C.99
  • D.5000

Answer: A

Recomputing with the reduced open-loop gain:

\[ A_{f} = \frac{5000}{1 + 50} \approx 98 \]

so about 98 - a fall of one per cent for a halving of the amplifier's own gain. That is desensitivity in a single calculation, and it is why a feedback amplifier can be built from devices whose parameters spread threefold and still meet a one per cent specification.

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