Discussion
An amplifier of gain \( 1000 \) and bandwidth \( 20 \ \mathrm{kHz} \) is given feedback to a closed-loop gain of \( 100 \). Its bandwidth becomes about
Answer: B
The gain has fallen tenfold, so the bandwidth rises tenfold:
\[ \begin{aligned} B_{f} &= 20\mathrm{k} \times \frac{1000}{100} \\ &= 200 \ \mathrm{kHz} \end{aligned} \]
giving about 200 kHz, with the gain-bandwidth product held at twenty megahertz throughout. That the product is the same before and after is worth checking on every such calculation, since it catches a direction error at once.
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