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Why does the feedback network's own tolerance matter so much?

  • A.Its capacitance sets the loop's stability margin
  • B.The closed-loop gain is set by it alone
  • C.It carries the full output current of the amplifier
  • D.Its noise is amplified by the open-loop gain

Answer: B

With a large loop gain the closed-loop gain is the reciprocal of the feedback fraction, so the network's component tolerances appear directly in the answer with no reduction whatever. It carries a small fraction of the output current, its noise is not amplified by the full open-loop gain, and stray capacitance affects stability separately. Feedback transfers the accuracy requirement from the devices to a handful of passive components, and those components must then be worth trusting.

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